The ground-state electron configuration of E) K B) Cr C) V D) Fe A) Mn 10) The p
ID: 1039455 • Letter: T
Question
The ground-state electron configuration of E) K B) Cr C) V D) Fe A) Mn 10) The principal quantum number for the outermost electrons in a Ca atom in the ground state is A) 3 B) 5 C) 6 D) 4 11) The lowest orbital energy is reached when the number of electrons with the same spin is maximized. This statement describes Al Hund's rule B) Heisenberg Uncertainty Principle C) Planck's constant D) deBroglie hypothesis E) Pauli Exclusion Principle 12) Which of the subshells below do not exist due to the constraints upon the angular momentum 12) quantum number? A) 2s C) 2p D) all of the above E) none of the above 13) If an electron has a principal quanturn number (n) of 3 and an angular momentum quantum number (1) of 2, the subshell designation is A) 4d C) 4s D) 4p E) 3d 14) The largest principal quantum number in the ground state electron configuration of aluminumis 14) A)3 C) 4 15) Of the choices below, which gives the order for first ionization energies? A) Ar > Cl > S > Si > Al B) CI S Al Si> Ar D) Al > Si>S CI> Ar E) CI S> Al> Ar > S 16) There are unpaired electrons in a ground state phosphorus atom. 16) A) 4 C)0 E) 2 17) Of the following transitions in the Bohr hydrogen atom, the transition results in the 17) emission of the highest-energy photon C)n 1-n-4 E)n 6-n-3 D-2Explanation / Answer
[9] the answer is (B) Cr
[Ar] 4s1 3d5 Atomic number = 18 (of Ar) +1+5 = 24, which corresponds to Cr
[10] the answer is (D) 4
Ca (Atomic number 20); electronic configuration: [Ar] 4s2 . As the outermost electron belongs to 4s, Principle quantum number is 4
[11] the answer is (A) Hund's rule
Hund's rule of maximum multiplicity states that 'the lowest energy atomic state is the one which have the maximum total spin quantum number for the electrons'.
[12] the answer is (B) 2d
For principle quantum number 2 angular momentum quantum number can have two values 0 and 1. 0 corresponds to 's' and 1 corresponds to 'p'. So, for principal quantum number 2 only 2s and 2p exist. Thus, the answer is 2d, which does not exist for principal quantum number 2.
[13] the answer is (E) 3d
n= 3 and l=2 which is assigned symbol 'd'
thus, 3d
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