The formation of Cd(II) complexes with Br- exhibit the following successive equi

Question

The formation of Cd(II) complexes with Br- exhibit the following successive equilibrium constants in water: log K1 -1.56, log K2- 0.54, log K3- 0.06, log K45- 0.37. Starting with [Cd(OH2)s]2+, write down the chemical equation for each step, write the equilibrium expression for each step and calculate the equilibrium constant (Kn) at each step. The coordination complex product of the fourth reaction is [CdBra]2. Knowing this, explain why K4 is larger than Ks Calculate the overall formation constant (B) for [CdBr4]2

Explanation / Answer

Overall stability constant =logk1+.......logK4

=1.56+.54+.06+.34=ans

Due to more bromine attach among complex of Cd then there

Have sterically hinderence and space comes to left

For the last bromine attack to complex of cadmium..hence

Last constant value for attaching bromine will be more than before it ...

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