Advance Study Assignments Molar Mass of an Acid also be found by Eiquation 1, un

Question

Advance Study Assignments Molar Mass of an Acid also be found by Eiquation 1, uning the final wohume of the uton Calae that melanit 2. 2nanacidha?titration, 22.13 mL of an NaOH solution .re nooded·o 2465 mL of a 0 1094 M HCI solution. To find the molarity of the NaoH solution, we can use the following procedure Finst note the value of M,r in the HC1 solution h Find Mor in the NaOH solution (Use Eq 3) c. Obtain M from Mo A 0.2678 g sample of an unknown acid requires 27.21 mL of 0.1164 M NaOH for neutralization to a phenolphthalein end point. There are 0.35 mL of 0.1012 M HCI used for back-titration. How many moles of OH are used? How many moles of H from HCI? moles OH- moles H+ How many moles of H' are there in the solid acid? (Use Eq. 5.) moles H' in soli What is the molar mass of the unknown acid? (Use Eq. 4.)

Explanation / Answer

I am solving the Q1 with multiple sub-parts as per Chegg guidelines, post multiple question to get the remaining answers

Q1)

a) Number of moles of NaOH = Volume of solution (in L) * Molarity of NaOH (M)

=> 7.0/1000 * 6M

=> 0.042 moles

b) Since on dilution, the number of moles will remain the same

Number of moles (after dilution) = Number of moles (before dilution) = 0.042 moles

Volume of diluted solution = 600 mL = 0.6 L

Number of moles = Volume of solution(in L) * molarity(M)

0.042 = 0.6L * Molarity

Molarity = 0.07M

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.