Ksp= 7.40x10^-14 Formula BaCrO4 1.17x10-10 BaSO4 1.08x 10-10 Cacos 3.36x109 Caf2

Question

Ksp= 7.40x10^-14

Formula BaCrO4 1.17x10-10 BaSO4 1.08x 10-10 Cacos 3.36x109 Caf2 3.45x10-11 Calculate the solubility at 25 °C of PbCO, in pure water and in a 0.0100 M Pb(NO), solution Round both of your answers to 2 significant digits. Co(OH)2 5.92x10-15 solubility in pure water: 6.27x10-S 1.4x10-10 Fe(OH)2 4.87x10 1 Pbco2 7.40x10-14 PbCrO4 2.8x1013 PbF2 3.3x10-8 Mg(OH)2 5.61x10-12 Ni(OH)2 5.48x10-16 AgBrO3 5.38x10-5 Ag2C03 8.46x10-12 AgC 1.77x10-10 Ag2Cro4 1.12x10-12 CuBr CuCO3 solubility in 0.0100 M PbNO3)2n solution Explanation

Explanation / Answer

in pure water :

PbCO3   ------------> Pb+2   +   CO32-

                                    S              S

Ksp = [Pb+2][CO32-]

7.40 x 10^-14 = S^2

S = 2.72 x 10^-7 M

solubility = 7.27 x 10^-5 g / L

in Pb(NO3)2 :

PbCO3   ------------> Pb+2   +   CO32-

                                   0.01             S

Ksp = [Pb+2][CO32-]

7.40 x 10^-14 = 0.01 x S

S = 7.4 x 10^-12

solubility = 1.98 x 10^-9 g/ L

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