28. The energy of a particle in a three-dimensional box with equal sides is give

Question

28. The energy of a particle in a three-dimensional box with equal sides is given by Ernsyn - (ni +n+n?) where n y, and n, are the quantum numbers defining an independent state. The degeneracies of the first, second, and third energy levels are (A) 1, 2, 3 (B) 1, 3, 1 (C) 1, 3, 3 (D) 1, 2, 2 29. The Schrödinger equation for a particle in a three dimensional box is ANYJ-ev Eos The separation of variables technique allows the wave function, y, and the energy E to be written as Vlky) (A) v()+v,60)+v(e) E,E,E: (8) Viv, (v)v:(€) E,+E, + E; + v,(1)+ v:(8) E, + Ey + E; PD) vajov)v(:) E,ELE: 36; Because the nucléar motions are much slower than those of the electron, the molecular Schrodinger equation for the electron motion can be solved by assuming that the nuclei are at fixed locations. This is (a) the Born-Oppenheimer approximation. (B) the time-dependent Schrödinger equation. (c) Russell-Saunders coupling (D) the variation method. 31. In the quantum mechanical solution for the rigid rotor, the square of the angular momentum is given by L2 = J(J+1)(n/2*)? HJ-2, the possible values for the z component of the angular momentum are (in units of h/2) (A), 2, 1, 0, -1, -2 (B) 1, 0, -1 (C) O (D) 2, 1,6 32. The lowest energy possible for a harmonic oscillator with an associated frequency () determined from quantum mechanics is (A) hv (B) zero (c) hv2 above the bottom of the potential well. (D) hv2 below the bottom of the potential well.

Explanation / Answer

the ansewrs of the above questions are ::::

these questions direct answering questions

28) A

29) B

30) A

31) A

32) A

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