if you could do 7.2 by hand please so i can see how its done the long way. thank

Question

if you could do 7.2 by hand please so i can see how its done the long way. thanks

Problem Set Solve the following problems using both the appropriate parametric and non- parametric tests. 7.1) The following data are the lengths of the menstrual cycle in days in a random sample of 15 human females. Determine if the mean length of human menstrual cycles is equal to a lunar month (a lunar month is 29.5 days). Data: 26, 24, 29, 33, 25, 26, 23, 30, 31, 30, 28, 27, 29, 26, 28 7.2) The following data are osmotic concentrations (mmol-g1) of the blood of an arthropod. Determine if the mean osmotic concentration of the blood of this animal is the same as the osmotic concentration of the water in which it lives. (The environmental osmotic concentration is 0.64 mmolg1.) Data: 0.66, 0.69, 0.68, 0.71, 0.70, 0.68, 0.66, 0.67, 0.63. 7.3) Body temperatures (C) were obtaincd from a sample of eight inter-tidal crabs exposed to air at 26.2 °C. Determine if the mean body temperature of this species of crab under these conditions is less than 26.2 °C. Data: 26.8, 25.6, 26.1, 25.9, 26.1, 25.7, 26.0, 26.5. iet The chanoes in weight (Kg)

Explanation / Answer

7.2 The mean data is given by sum of all data divided by the number of data.

So The osmotic concentrations given are-0.66, 0.69, 0.68, 0.71, 0.70, 0.68, 0.66, 0.67, 0.63

Total number of data = 9

Sum = (0.66 + 0.69+ 0.68+ 0.71+0.70+ 0.68+ 0.66+ 0.67+ 0.63) = 6.08

Therefore, mean osmotic concentration = 6.08 /9 = 0.675 mmol/g

So, mean osmotic pressure is more than the water.

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.