if the vertical initial speed of the ball is 4.5 m/s as the cannon moves horizon

Question

if the vertical initial speed of the ball is 4.5 m/s as the cannon moves horizon Tools Help View Favoritni Spring 2017 PHYS 1114 TRO4S Low Awheeled car with a spring Hoaded cannon sines a meta bal vertically (see the a Search More Sign H Google Page safety Tools. Hee vertical insal speed of the balus 4.s mVs as cannot horizontally at a speedol 50 m/s, how far from the launch point does the Be moves ball back into the cannon? Express your answer using two significant figu Incorrect, Try Again, 6 attempts remaining Part B What would happen the cannon were answers are limited to about 500 words (3800characters maximum, including spaces) 3800 Character(s0 remaining

Explanation / Answer

here,

the initial vertical speed , u = 4.5 m/s

time taken to reach ground maximum height be t

v = u - g * t

0 = 4.5 - 9.8 * t

t =0.46 s

a)

so the horizontal distance travelled , x = vx * (2 * t)

x = 0.5 * 2 * 0.46 m

x = 0.46 m

b)

if the cannon is accelrating

the ball will not accelrate after shotting from the cannon,

so the horizontal distance trravelled by the ball is less than the horiontal distance travelled by the cannon

the ball will come back into the cannon

it will fall before the cannon

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