study the following sketch of a molecular orbital study the following sketch of

Question

study the following sketch of a molecular orbital study the following sketch of a molecular orbital study the following sketch of a molecular orbital Solving limiting reactant problems in solution Suppose 0.407 g of sodium acetate is dissolved in 100. mL of a 44.0 m Maqueous solution of ammonium sulfate. Calculate the final molarity of sodium cation in the solution. You can assume the volume of the it. solution doesn't change when the sodium acetate is dissolved n Be sure your answer has the correct number of significant digits ALL

Explanation / Answer

moles of sodium acetate (CH?COONa) = 0.407/82 = 0.00496 mole

so, moles of sodium cation = 0.00496 mole

final volume of solution = 100 ml = 0.1 L

so final molarity of sodium cation = 0.00496/0.1 = 4.96 x 10^-2 M

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