Resources 4/10/2018 11:55 PM?0/100 Gradebook O Assignment t h Print el Periodic

Question

Resources 4/10/2018 11:55 PM?0/100 Gradebook O Assignment t h Print el Periodic Table Calculator Available Fror Due Date: Late Question 9 of 2 Sapling tearning submissions: Assuming complete dissociation, what is the pH of a 3.19 mg/L Ba(OH)2 solution? Number Points Possible Grade Categor Description: Policies: pH- You can check yo You can view solu give up on any qu You can keep tryl until you get It rig You lose 5% of the answer in your qu attemptat that an OeTextbook O Help With This in Check Answer NextEx

Explanation / Answer

Mass of Ba(OH)2 = 3.19 mg / L

Moles of Ba(OH)2 = 3.19 / 1000 x 171.34 = 1.861 x 10-5 Moles

We can calculate the pOH of the solution using the formula

pOH = - Log OH

pOH = - log 1.861 x 10-5 = 4.73

pH of the solution can be calculated usiing the formula

pH + pOH = 14

pH = 14 - pOH

pH = 14 - 4.73 = 9.26

pH of the solution is 9.26  

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