? Part A Constants | Periodic Table How many militers of 0.0520 M NaOH are requi

Question

? Part A Constants | Periodic Table How many militers of 0.0520 M NaOH are required to reach the equivalence point? Express your answer using two significant figures. Consider the titration of 100.0 mL of 0.014 M HOCl (Ka 3.5 x 10-8) with 0.0520 M NaOH. mL Submit Request Answer Part B Calculate the pH after the addition of 10.0 mL of 0.0520 M NaOH Express your answer using two decimal places. pH- SubmitR Request Answer ? Part C Calculate the pH halfway to the equivalence point. Express your answer using two decimal places. pH-

Explanation / Answer

part A)

mmoles of HOCl = 100 x 0.014 = 1.4

pKa = 7.46

At equivalence point :

mmoles of HOCl = mmoles of NaOH

1.4 = 0.0520 x V

V = 27 mL

volume = 27 mL

part B)

mmoles of NaOH = 10 x 0.0520 = 0.52

HOCl   +   NaOH    --------------> NaOCl + H2O

1.4          0.52                                0             0

0.88           0                               0.52

pH = pKa + log [salt / acid]

     = 7.46 + log [0.52 / 0.88]

pH = 7.23

part C)

pH = 7.46

part D)

concentration of salt = 1.4 / 100 + 27 = 0.0110 M

pH = 7 + 1/2 (pKa + log C)

     = 7 + 1/2 (7.46 + log 0.0110)

pH = 9.75

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