When Ln P is plotted vs. 1/T, a linear relationship should be observed. What doe

Question

When Ln P is plotted vs. 1/T, a linear relationship should be observed. What does the slope of that line represent? 3. a. Using the sample plot below, calculate the AHap (in units of kJ/mol) assuming R 8.314472 J,/ mol K. 3.0 Linear Fit for. Remote Data | Ln(Pvap) m (Slope:-3710.5765+252.2237 b (Y-Intercept): 14.4896 0.8268 Correlation:-0.9886 RMSE: 0.0459 2.5 2.0 0.00315 0.00320 0.00325 0.00330 0.00335 For the plot of Ln P vs. 1/T shown above the y-intercept is shown as 14.4896. Would it be possible for a y-intercept in this experiment to be zero? Explain why or why not. [Your response should define what a y-intercept is, what it represents in this graph and why it could or could not be zero in this experiment.] 4.

Explanation / Answer

Ans. The linear regression equation for Clausius-Clapeyron plot is in form of y = mx + c, where-

            y = ln P

            m = slope = (-dHvap / R)

            x = (1/T)

            c = y-intercept = ln (A)

# The slope of line represents (-dHvap / R)

#a. dHvap = - (slope x R) = - (-3710.5765 ± 252.2237) K x (8.314472 J mol-1 K-1)

                        = 446.2793 ± 30.3355 J mol-1

                        = 0.4463 ± 0.0303 kJ mol-1

#b. Y-intercept represent ln (A), where A = collision frequency.

Collison frequency is the rate of collision amount the molecules in the given system.

It is proportional to temperature in kelvin (among other non-zero factors). Since temperature can’t be experimentally brought to 0 K, the value of A can’t be zero.

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