A sample of argon gas at a pressure of 0.720 atm and a temperature of 26.6 °C, o

Question

A sample of argon gas at a pressure of 0.720 atm and a temperature of 26.6 °C, occupies a volume of 16.4 liters. If the gas is allowed to expand at constant temperature to a volume of 20.4 liters, the pressure of the gas sample will be atm. A sample of carbon dioxide gas at a pressure of 1.04 atm and a temperature of 26.6 °C, occupies a volume of 589 mL. If the gas is compressed at constant temperature until its pressure is 1.37 atm, the volume of the gas sample will be mL. A sample of methane gas at a pressure of 0.943 atm and a temperature of 20.3 °C, occupies a volume of 724 mL. If the gas is allowed to expand at constant temperature until its pressure is 0.692 atm, the volume of the gas sample will be mL.

Explanation / Answer

1.
       initial                            final
       P1 = 0.72atm                      P2 =
       V1 = 16.4L                        V2 =20.4L
                P1V1   = P2V2
                  P2   = P1V1/V2
                       = 0.72*16.4/20.4   = 0.578atm
2. initial                       final
   P1 = 1.04atm                 P2 = 1.37atm
   V1 = 589ml                    V2=
          P1V1 = P2V2
            V2   = P1V1/P2
                  = 1.04*589/1.37   = 447.12ml
3. initial                         final
   P1 = 0.943atm                  P2 = 0.692atm
V1    = 724ml                     V2 =
             P1v1   = P2V2
               V2   = P1V1/P2
                    = 0.943*724/0.692   = 986.6ml

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