I need help getting the calculations of corrected mass and molecular weight in t

Question

I need help getting the calculations of corrected mass and molecular weight in this experiment. Please include how you got the answers so that I understand.

BLE 10.I1 Mass, pressure, temperature, and volume measuremen Unknown number Mass of flask and foil (g) easurements. Run 1 Run 2 Run 3 Estimated Mas of lask, foil, and condensed vapor (g) .000 11-62 71.0(aGG?·622ip 98S Error ±.06 ±.00 ienperature of boiling water bath (°C) Volume of flask (mL) Barometric pressure (mmHg) Room temperature (C) Vapor pressure at room temperature (mmHg) 106 Instructor's initials d CALCULATIONS Table 10.2 Calculation of corrected mass and molecular weight. Run 1 Run 2 Run 3 Maximum Error Uncorrected mass of condensed vapor (g) Corrected density of air (g/L) Average volume of flask (L) Initial mass of air in flask (g) Final partial pressure of air in flask (mmHg) Final mass of air in flask (g) Mass of air lost (g) Corrected mass of condensed vapor (g) Molecular weight (g/mol) Average molecular weight (g/mol) Average deviation (g/mol)

Explanation / Answer

Answer:

1) Uncorrected mass of condensed vapour = 65.5519 - 65.4950 =0.0569 gm

2) density of air = mass / volume = 0.0569 gm/152 mL = 0.0569gm/ 0.152L = 0.374 gm/L

3) Average volume of flask = (0.152 + 0.152) L / 2 = 0.152 L

4) Mass of air = density * volume = 0.152 L * 1gm/L = 0.152gm

5) Final partial pressure = 762 -100 = 662 mmHg

6) final mass of air = 0.152 - 0.0569 = 0.0951 gm

7) mass of air lost = 0.0569 gm

8) corrected mass of condensed vapour = 0.0951 - 0.0569 = 0.0382gm

9) Molecular weight = mass/number of moles = 0.0382 gm /(PV/RT)

   = 0.0382 gm / (662mmHg*0.152L / 62.364L.mmHg/mol.K * 299K)

   = 0.0382 gm /(100.624 / 18646.84 mol)

   = 0.0382 gm /0.0054 mol

   = 7.1 gm/mol

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