Consider the reaction Mg(s)+F e 2+ (aq)?M g 2+ (aq)+Fe(s) at 63 ? C , where [F e

ID: 1046413 • Letter: C

Question

Consider the reaction Mg(s)+F e 2+ (aq)?M g 2+ (aq)+Fe(s) at 63 ? C , where [F e 2+ ]= 2.80 M and [M g 2+ ]= 0.310 M .

Part A

What is the value for the reaction quotient, Q , for the cell?

Part B

What is the value for the temperature, T, in kelvins?

Express your answer to three significant figures and include the appropriate units.

Part C

What is the value for n?

Express your answer as an integer and include the appropriate units (i.e. enter mol for moles).

Part D

Calculate the standard cell potential for

Mg(s)+Fe2+(aq)?Mg2+(aq)+Fe(s)

Express your answer to three significant figures and include the appropriate units.

Mg(s)+F e 2+ (aq)?M g 2+ (aq)+Fe(s)

Mg(s) -------------------> Mg^2+ (aq) + 2e^- E0 = 2.38v

Fe^2+ (aq) + 2e^- ---------> Fe(s) E0 = -0.41v

---------------------------------------------------------------------------------

Mg(s)+F e 2+ (aq)?Mg 2+ (aq)+Fe(s) E0cell = 1.97v

n = 2

Q = [Mg^2+]/[Fe^2+]

= 0.31/2.8 = 0.11

T = 63+273 = 336K

Ecell = E0cell - RT/nF lnQ

= 1.97 - 8.314*336/2*96500 ln0.11

= 1.97 -0.0145ln0.11

= 1.97-0.014*-2.2072 = 2.00v

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.