Given- Li+ (aq) + e– ––> Li(s) E° = –3.04 V 2H+ (aq) + 2e– ––> H2(g) E° = 0.00 V

Question

Given- Li+ (aq) + e– ––> Li(s) E° = –3.04 V 2H+ (aq) + 2e– ––> H2(g) E° = 0.00 V

2H2O(l) + 2e– –> H2(g) + 2OH– (aq) E° = –0.83 V S2O82– (aq) + 2e– –> 2SO42– (aq) E° = 2.01 V

O2(g) + 4H+ (aq) + 4e– –––> 2H2O(l) E° = 1.23 V

What are the expected products when an aqueous solution of lithium sulfate (Li2SO4) is
electrolyzed using inert electrodes? Any of the half-reactions listed above may be involved.
A) Li(s) and H2(g)
B) H2(g), OH– (aq), O2(g), and H+(aq)
C) O2(g), H+ (aq), and Li(s)
D) H2(g), OH– (aq), and Li(s)
E) H2(g), OH– (aq), and S2O82– (aq)

Explanation / Answer

Li+ (aq) + e– ––> Li(s)            E° = –3.04 V   at cathode

2H2O(l)------------->O2(g) + 4H+ (aq) + 4e–    E° = 1.23 V at anode

C) O2(g), H+ (aq), and Li(s)

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