Given two vectors F 1 , and F 2 . Where themagnitude of these vectors are F 1 =

Question

Given two vectors F1, and F2. Where themagnitude of these vectors are F1= 91N, andF2= 70N. And where 1=166, and2=216. The angles are measure from the positive xaxis with the counter-clockwise angular direction as positive. Whatis the magnitude of the resultant vector ||F||, where F=F1 + F2? Answer in units of N. Ialready worked this part out and I got 146.185205 and its right,but I just dont know how to do the next part. Please help me.Thanks b.) Give the angle in degrees, use counterclockwise as thepositive angular direction, between the limits of -180degrees and +180 degrees from the positive x axis. Whatis the direction of this resultant vector F. Answer in units ofdegrees. Given two vectors F1, and F2. Where themagnitude of these vectors are F1= 91N, andF2= 70N. And where 1=166, and2=216. The angles are measure from the positive xaxis with the counter-clockwise angular direction as positive. Whatis the magnitude of the resultant vector ||F||, where F=F1 + F2? Answer in units of N. Ialready worked this part out and I got 146.185205 and its right,but I just dont know how to do the next part. Please help me.Thanks b.) Give the angle in degrees, use counterclockwise as thepositive angular direction, between the limits of -180degrees and +180 degrees from the positive x axis. Whatis the direction of this resultant vector F. Answer in units ofdegrees.

Explanation / Answer

b.)the magnitude of the resultant force is |F| = (Fx^2 + Fy^2)^(1/2) Fx = F1x + F2x = F1 * cos1 + F2 * cos2 and Fy = F1y + F2y = F1 * sin1 + F2 * sin2 F1 = 91 N and F2 = 70 N 1 = 166o and 2 = 216o or Fx = 91 * cos(166o) + 70 * cos(216o)= -88.3 + (-56.6) = -144.9 N and Fy = 91 * sin(166o) + 70 * sin(216o)= 22.0 + (-41.1) = -19.1 N the direction of the resultant vector F is tan = (Fy/Fx) = (-19.1/-144.9) or = tan-1(-19.1/-144.9) = 7.5ocounterclockwise from the positive x axis

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