a) At physiological temperature (37 o C) the osmotic pressure of blood is 7.65 a
ID: 1047946 • Letter: A
Question
a) At physiological temperature (37oC) the osmotic pressure of blood is 7.65 atm. If you are preparing a dextrose solution for injection, how many milligrams of dextrose (180 g/mole) do you need to add to 500 mL of sterile water to make this product isotonic with blood? (R = 0.0821 L-atm/mol-deg)?
b) When 5.2 grams of an unknown compound is added to 450 mL of water, the freezing point of the solution is – 0.28OC. What is the molecular weight of the compound? (assume i = 1; Kf = 1.86 deg-kg/mol).
c) What is the boiling point for an aqueous solution containing 100 grams of NaCl in 2 Liters of water. The eubllioscopic constant of water is 0.513 deg-kg/mole, and the molecular weight of NaCl is 58.5 g/mole.
Explanation / Answer
a)
P = MRT
M = P/(RT) = 7.65/(0.082*(37+273)) = 0.3009441 M
mol = MV = 0.3009441*05 = 0.1504 mol
mass = mol*MW = 0.1504*180 = 27.072 g = 27.072*10^3 mg
b)
m = 5.2 g of x
V = 450 mL
dT = -0.28
assume
dT = Kf*m
m = mol S / kg solvent
m solvent = 450 g = 0.45 Kg
-0.28 = -1.86*mol/0.45
mol = 0.28*0.45/1.86 = 0.0677419 mol
so
MM = mass/mol = 5.2/0.0677419 = 76.761 g/mol
c)
m = 100 g of NaCl in V = 2 L
Kb = 0.513
Tb = Kb*m*i
i = 2 ions, NA+ + Cl-
mol = mass/(MW = 100/58.5 = 1.7094 mol
mas sin kg = 2 L = 2 kg
molal = 1.7094/2 = 0.8547 molal
dTB = 0.513*0.8547*2 = 0.87692 °C
100.87692 °C
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