Write the balanced chemical equation for the decomposition of potassium chlorate

Question

Write the balanced chemical equation for the decomposition of potassium chlorate that you will be observing in this experiment. Include state of matter. What is the purpose of the manganese (IV) oxide that is present in the unknown sample? What do you think would happen without it? One potential source of error stems from the fact that heat is applied to the test tube to initiate the reaction. Discuss why this might cause an error, and whether your calculated R will be too high or too low. If the water level within the gas collection bottle is higher than the water level in the through, is the pressure in the bottle higher or lower than the bottle higher or lower than the atmospheric pressure? Why is it important to remove the latex tubing from the gas collection bottle after the decomposition is complete? A student measures out 2.050 g of sample. After the reaction, the residue has a mass of 1.673 g. What is the percent by mass of potassium chlorate in the sample?

Explanation / Answer

1) The decomposition reaction can be expressed as:-

2KClO3(s) ----MnO2--------------> 2KCl(s) + 3O2(g)

Here MnO2 acts as a catalyst

2) The manganese(iv) oxide that is present in the unknown sample .It acts as a catalyst for the decomposition reaction .

If we don't add manganese to the unknown sample then the desired reaction takes place along with some other side reactions.

4 KClO3(s) -----------> 3 KClO4(s) + KCl(s)

further heating will result in :-

KClO4(s) KCl(s) + 2 O2(g)

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