CH,0h(l) CH3OH(g) {.vap is 38 kj/mol 12)How much heat is required to vaporize 64

Question

CH,0h(l) CH3OH(g) {.vap is 38 kj/mol 12)How much heat is required to vaporize 64 g of methanol? a. 19 k b. 38 k c. 57 k d. 76 k 13)The normal boiling point of a substance is defined to be the temperature at which the liquid phase of the substance is in equilibrium with the gas phase at 1 atm pressure. If the normal bailing point of methanol is 80°C and the am'vap is 38 kJ/mol, what is .ap at 80°C? A +108 1/mol-K B -108 J/mol-K C +475 J/mol-K D -475 1/mol-K E +3040 1/mol-K 14)Which of the following correctly expresses the relationship between the enthalpy of a system and the entropy of the surroundings? 15)At25°C dry ice (solid carbondioxide) spontaneously sublimes cols) CO2(g) Given than Hs 15 kJ/mol and ASSUB A ASUNIV = 0 J/mol-K B ASUNIV = +90 J/mol-K c, asUNIys +1401/mol-K 140 J/mol-K, what is as,Nr for this process E ASUNIV=-4601/mol-K t6)Use the diagram below to consider the transport of sodium ions across a cell membrane in the 6)Use the diagram below to consider the transport human body at 37°C. What is the free energy per mole to transport sodium ions across the cell membrane and into the extracellular matrix? A -0.338 k]/mol B +2.34 k)/mol C -2.34 k]/mol D +2.8 kl/mol Extracellular natrik Nat D.05M 2 Insidetel [Na+] D.15M 3 E 2.83 kl/mol

Explanation / Answer

Moles of methanol = 64gm/32gmmol^-1 = 2 moles

heat required to vaporize 2 moles of methanol = 38kJ/mol *2 = 76 kJ

Answer : d

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dS = dH/T = 38*10^3 J/mol/(273+80) K = 108 J/mol/K

abswer : A

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Answer : A

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dS(univ) = ds(sys) + dS(surr)

= 140J/mol/K - 15,000J/mol/298 K

=89.66 J/mol/K ~90 J/mol/K

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