Pre-Lab Questions: 1. Calculate the amount of the above salts needed to make 20
ID: 1050460 • Letter: P
Question
Pre-Lab Questions: 1. Calculate the amount of the above salts needed to make 20 mLof1.0M solution and fill in 2. Tablel whether they Name the cations and anions produced by the dissolution of the salts and state will undergo any hydrolysis and complete Table 2. and decide 3. Complete Table 3 by writing the hydrolysis equation for the cations and the anions if the solution is neutral, acidic or basic. Table 1 Amount of the salt for 20 mL 1.0M Solution Solution NaCI NaOCOCH3 NH4Cl NaHCOs Na2SOs Table 2 Cation form Anion from the Hydrolysis of Spectator ion if any Solution The solution solution Cation or anion 1.0 M NaCl 1.0M NaOCOCH, 1.0MNHaCIT 1.0M Nalco, 1.0M NazsoExplanation / Answer
Compound
Molar mass
Moles= Molarity* Volume (L)
Mass= moles* Molar mass (gm)
NaCl
58.5
0.1*20/1000 = 0.002
.002*58.5= 0.117
CH3COONa
82
0.002
0.002*82=0.164
NH4Cl
53.5
0.002
0.002*53.5= 0.107
NaHCO3
84
0.002
84*0.002=0.168
Na2SO3
126
0.002
126*0.002=0.252
Compound
Cation
Anion
NaCl
Na+
Cl-
CH3COONa
Na+
CH3COO-
NH4Cl
NH4+
Cl-
NaHCO3
Na+
HCO3-
Na2SO3
2Na+
S2O3-2
the reactions are not hydrolyssis just dissolutino in water,
NaCl (aq)------> Na+ +Cl- K= [Na+] [Cl-]/ [NaCl]
CH3COONa(aq)---->CH3COO- + Na+ K= [CH3COO-] [Na+]/ [CH3COONa]
NH4Cl (aq)--------> NH4+ +Cl- K= [NH4+] [Cl-]/ [NH4Cl]
NaHCO3- (aq)----->Na+ + HCO3- K= [Na+] [HCO3-]/ [NaHCO3]
Na2SO3 (aq)---->2Na+ +S2O3- K= [Na+]2 [S2O3-]/ [Na2SO3]
Compound
Molar mass
Moles= Molarity* Volume (L)
Mass= moles* Molar mass (gm)
NaCl
58.5
0.1*20/1000 = 0.002
.002*58.5= 0.117
CH3COONa
82
0.002
0.002*82=0.164
NH4Cl
53.5
0.002
0.002*53.5= 0.107
NaHCO3
84
0.002
84*0.002=0.168
Na2SO3
126
0.002
126*0.002=0.252
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