this question was wrtten by Gen Chem Lab Coordinator at Western Washington Unive
ID: 1050759 • Letter: T
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this question was wrtten by Gen Chem Lab Coordinator at Western Washington University (W Explain why the conductivity of 0.065 M Li2SO4(aq) is greater than that of 0.065 M NaBr(aq) Conductivity increases when electrolytes react with water. Li2S04 reacts much O more readily with the water than NaBr, thus the greater reactivity of Li2SO4 will lead to a much greater conductivity in solution. lon size can play a big part in electrical conductivity. Some or all of the ions in NaBr are much smaller than the ions in Li2S04, thus the ions in Li2S04 are better able to conduct the electricitv. Electrolytes with a S04 anion will always have a higher conductivity when compared to any other electrolyte. Thus the Li2SO4 will always have a higher conductivity than NaBr as long as they are at the same concentration The total ion concentration of the Li2S04 is greater than the NaBr. In addition, some or all of the ions in Li2SO4 have higher charge than those of NaBr. Both of these factors increase the conductivity of the Li2S04 solution. O The NaBr is a weak electrolyte while the Li2S04 is a strong electrolyte. Thus the Li2SO4 fully ionizes in solution and will have a higher conductivity than the NaBr.Explanation / Answer
0.065 M Li2SO4 is having greater conductivity than 0.065 M NaBr
Conductivity depends on the number of ions in solution. Li2SO4 gives 3 ions while NaBr gives only 2 ions. Hence the Li2SO4 solution has greater conductivity.
The correct answer is: total ion concnetration of Li2SO4 is greater than the NaBr. In addition some or all of the ions in Li2SO4 have higher charge than those of NaBr. Both of these factors increase the conductivity of the Li2SO4 solution.
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