I\'m confused about the % error. I know the equation is |(actual-experimental)/a

Question

I'm confused about the % error. I know the equation is |(actual-experimental)/actual| *100 The problem is I don't know which is which. I have 3 trails show the molarty 1- 0.2009 M 2- 0.2032 M 3- 0.2016 M And the average molarty = 0.2005 M Can any explain to me how to solve the % error I'm confused about the % error. I know the equation is |(actual-experimental)/actual| *100 The problem is I don't know which is which. I have 3 trails show the molarty 1- 0.2009 M 2- 0.2032 M 3- 0.2016 M And the average molarty = 0.2005 M Can any explain to me how to solve the % error The problem is I don't know which is which. I have 3 trails show the molarty 1- 0.2009 M 2- 0.2032 M 3- 0.2016 M And the average molarty = 0.2005 M Can any explain to me how to solve the % error

Explanation / Answer

experimentally average molarity= (0.2009 M + 0.2032 M + 0.2016 M)/3=0.2019 M

% of error= |(actual-experimental)/actual| *100

% of error= |(0.2005-0.2019)/0.2005| *100

% of error= 0.698%

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