Data and Calculations 29.5 9X 25,397 Trial 2 Trial 1 040 Data: Unknown Sample id
ID: 1052045 • Letter: D
Question
Data and Calculations 29.5 9X 25,397 Trial 2 Trial 1 040 Data: Unknown Sample identifier Mass of sample (except for preweighed sample) 3,00 volume of uncalibrated portion of buret (Method A) mL. mL. mL. Final buret reading (Method A) 23 Volume of hydrogen orr 100 Temperature of hydrogen mm Hiro Barometric pressure (Method A) 56 mm Hao Difference in water inside and outside tube levels Aqueous vapor pressure at temperature of hydrogen Trial 2 Trial 1 23.52x25.37 Data mm Hg (torr) equivalent of difference 103 4, 748 torr 135 of water levels (Method A) rressure of H, after correction for erence in Hao levels and for vapor pressure Temperature, absolute mL. volume of dry H, at standard g/equiv toodutions, e., corrected for vapor Pressure, pressure and temperature Ecentage of relative error be changed as necessary, depending whether you are reperung Your value-accepted value. x 100 preweighed ample, or theExplanation / Answer
From the data
Trial 1
P = (779.5 - 4.75) = 774.75 = 1.02 atm
Volume = 4.5 ml = 0.0045 L
T = 22 oC = 22 + 273 = 295 K
moles of H2 (n) = PV/RT = 1.02 x 0.0045/0.08205 x 295 = 0.0002 mols
Equivalent mass = 0.040/0.0002 = 200
Trial 2
P = (779.5 - 3.704) = 775.80 = 1.021 atm
Volume = 8.5 ml = 0.0085 L
T = 22 oC = 23 + 273 = 296 K
moles of H2 (n) = PV/RT = 1.021 x 0.0085/0.08205 x 296 = 0.00036 mols
Equivalent mass = 0.040/0.00036 = 112
Average = 156
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.