Data and Calculation (show all calculations): Name of the antacid brand Active i
ID: 504875 • Letter: D
Question
Data and Calculation (show all calculations): Name of the antacid brand Active ingredient from label Amount of HCI added to the antacid, 0.00200 L times 0.100 M mole NaOH titration against excess HCI Mole NaOH = M times V (in L) = (0.100) L NaOH used) HCI used in neutralizing the antacid (base): 0.200 - NaOH mole used in titration HCI___ mole ___ mole ___ mole Mass of antacid weighed ___ g ___g ___g Neutralizing power of antacid, mole of HCI (stomach acid)/g antacid ___ ___ ___ Average neutralizing power, mole HCI/g antacid ___Explanation / Answer
CaCO3 + 2HCl ---> CaCl2 + H2CO3
NaOH + HCl ---> NaCl + H2O
Total HCl added = 0.1 M x 2 ml = 0.2 mmol
moles NaOH = grams NaOH/40 g/mol
Trial 1 Trial 2 Trial 3
NaOH (mmol) 0.5 0.5 0.5
Since moles of NaOH is greater than the total moles of HCl added, some discreapancy exists in the volume of HCl and/or mass of NaOH used.
moles of HCl used for neutralizing = total moles of HCl added - moles of NaOH used
From this data,
neutralizing power of antacid, which is = moles of HCl/grams of antacid
is calculated
From three trial runs, average value can be calculated easily.
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