Calculate the number of components present in each of the following situations:

Question

Calculate the number of components present in each of the following situations: (a) Water, including autodissocialion into H^+ and OH^- ions. (b) Consider the following reaction in a closed container: 2NH_3(g) N_2(g) + 3H_2(g) (i) All three gases were present initially in arbitrary amounts, but the temperature is too low for the reaction to occur. (ii) Same as (i), but the temperature is raised sufficiently to allow for the equilibrium to be established. (iii) Initially only NH_3 was present. The system is then allowed to reach equilibrium.

Explanation / Answer

1) the number of components will be = number of chemcial species - restrictions

Chemical species = H2O , H+ and OH-

Restriction

H2O --> H+ + OH-

So number of components =3-1 = 2

2) a) Three gases, no reaction

Components =3

b) three gases , reaction occur

C = Ne – r

Ne = number of gases in equilibrium

r= restriction

2NH3 --> N2 + 3H2

Components = 3-1 =2

c) one gas (NH3) then equilibrium

one component system

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