To understand the components and processes of a galvanic cell. A galvanic cell (

Question

To understand the components and processes of a galvanic cell. A galvanic cell (or voltaic cell) produces electricity using a spontaneous redox reaction, such as the one shown here: Fe(s)+Cu2+(aq)Fe2+(aq)+Cu(s) The components of this reaction are separated by a salt bridge and connected with a wire, forcing the electrons to travel across the wire, creating electricity.

Part A Describe the electrodes in this iron-copper galvanic cell. Drag the appropriate items to their respective bins.

anode, Cathode, gain mass, loses mass to Iron or Copper

Standard reduction potentials for iron(II) and copper(II)

The standard reduction potential for a substance indicates how readily that substance gains electrons relative to other substances at standard conditions. The more positive the reduction potential, the more easily the substance gains electrons. Consider the following:

Fe2+(aq)+2eFe(s),Cu2+(aq)+2eCu(s),   Ered=0.450 V   Ered=+0.337 V

Part B

What is the standard potential, Ecell, for this galvanic cell? Use the given standard reduction potentials in your calculation as appropriate.

Express your answer to three decimal places and include the appropriate units.

Explanation / Answer

A)

The anode --> oxidation occurs here, soFe must go here

the cathode --> reduction occurs here, so Cu cell must go here

the cathode will gain mass, since the Cu+2 goes fo Cu(s)

the anode will loss mass, since Fe(s) goes to Fe+2(aq)

PaRT B

Fe2+(aq)+2eFe(s) Ered=0.450 V

Cu2+(aq)+2eCu(s), Ered=+0.337 V

The most possitive will reduce, so Fe is going to oxidize,

Then

E°cell = Ered - Eox = 0.337 - (-0.45) = 0.787 V

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