Does this help? This is the question is written and these are the answers. 1 & 2
ID: 1054605 • Letter: D
Question
Does this help?
This is the question is written and these are the answers.
1 & 2.
3. In the titration of a weak acid with a strong base.
The pH at 10% of the equivalence point volume is approximately pKa-1
and,
The pH at 90% of the equivalence point volume is pKa+1
We will analyze this assumption using a Hendersen-Hasselbalck equation
pH = pKa + log(base/acid)
with,
10% of the equivalence volume,
[Base] = 10
[Acid] = 90
So,
pH = pKa + log(1/9)
pKa - 0.96
So the pH would be about 1 unit less than pKa, that is, pH = pKa - 1
When, 90% volume of the equivalence volume is placed
[Base] = 90
[acid] = 10
so
pH = pKa + log(90/10)
= pKa + 0.96
So the pH would be about 1 unit higher than pKa, that is, pH = pKa + 1
What is the minimum pH change required for a sharp indicator color change at the end point? Why? Fraction curve A = equivalent pH. B = amount of math require to neutralized Hel. C = equivalent point.Explanation / Answer
Yes the way is correct. Our eyes can see the color change when the ratio is around 1: 10 for salt and acid.
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