The boiling points (in degree C) of pentane and dodecane in PubChem, and record

Question

The boiling points (in degree C) of pentane and dodecane in PubChem, and record them below and in your lab notebook. In this experiment, you will be distilling a 1:1 mixture of pentane and dodecane. If the mixture is injected into the gas chromatograph without distilling first, which component do you think will come off the gas chromatograph first, and why? Continued from Question 2 above... how do you think the area of the peak for pentane will compare to the area of the peak for dodecane? Why?

Explanation / Answer

1.Boiling point of pentane , C5H12= 36.1o C
Boiling point of cyclohexane, C6H12 = 80.74 o C

2. Higher the boiling point of a liquid, the higher is its retention time. So Pentane would
   come off the gas chromatograph first as its Boiling point is less

3. The area of each peak is proportional to the amount of chemical present in the sample.
But since they are mixed in 1:1 ratio the area of pentane will be slightly less than
Cyclohexane

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