Calculate the energy of the photon emitted from the hydrogen atom in the Lyman s

ID: 1056047 • Letter: C

Question

Calculate the energy of the photon emitted from the hydrogen atom in the Lyman series with n2=42=4.

a2.04 x 10^16 J

b2.04 x 10^18 J

c2.04 x 10^20 J

d2.04 x 10^22 J

The first line in the Lyman series for hydrogen is 121.556 nm. Calculate the energy of the emitted photon.

a1.63 x 10^16 J

b1.63 x 10^17 J

c1.63 x 10^18 J

d1.63 x 10^19 J

What is the wavelength of a 27 g bullet that is fired from a gun with a velocity of 765 m/s?

Calculate the energy of the photon emitted from the hydrogen atom in the Lyman series with n2=42=4.

E = -13.6*(1/n1^2 - 1/n2^2) eV
= -13.6*(1/1 - 1/4^2)
= -13.6*15/16 eV
= -12.75 eV
= -12.75 * 1.602*10^-19 J
= -2.04*10^-18 J

Answer: b

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