The following reaction was performed: 4 25 mL of 2-methyl-2-hexanol (density 0.8
ID: 1056153 • Letter: T
Question
The following reaction was performed: 4 25 mL of 2-methyl-2-hexanol (density 0.812 g/mL, Mol. Wt 116 g/mol) was mixed with 14.8 mL of 12M hydrochloric acid to form 2-chloro-2-methylhexane (Mol Wt 134.5 g/mol). If 3.58 grams of 2-chloro-2-methylhexane were isolated, then what was the percent yield? 3.58% 81.8% 89.5% 84.2% You measure out material on the balance. The balance display reads 1.2000 g. Which of the following describes what you should do with this number. Record 1.2000 g in your notebook. Later neatly write this on datasheet. Record 1.2 g in your notebook. Later neatly write this on datasheet.Explanation / Answer
density of 2-methyl 2- hexnol = 0.812 gm/ml, and volume = 4.25 ml
mass = density x volume = 0.812 x 4.25 = 3.451 gm
mole of 2-methyl 2- hexnol = 3.451 / 116 = 0.02975 mole
No. of mole of HCl = molarity x volume of solution in liter
No. of mole of HCl = 12 x 0.0148 = 0.1776 mole
According to reaction 1 mole of 2-methyl 2- hexnol react with 1 mole of HCl then, 0.02975 mole of 2-methyl 2- hexnol require 0.02975 mole of HCl for complete reaction but HCl given 0.1776 thus it is excess reactant and 2-methyl 2- hexnol is limiting reactant react completly
According to reaction 1 mole of 2-methyl 2- hexnol produce 1 mole of 2-chloro 2- methyl hexane then 0.02975 mole of 2-methyl 2- hexnol produce 0.02975 mole of 2-chloro 2- methyl hexane.
molecular weight of 2-chloro 2- methyl hexane is 134.5 gm/mol that mean 1 mole of 2-chloro 2- methyl hexane = 134.5 gm then0.02975 mole of 2-chloro 2- methyl hexane = 0.02975 x 134.5 = 4.001375 gm
4.001375 gm 2-chloro 2- methyl hexane = theoritical yield = 100%
then 3.58 gm 2-chloro 2- methyl hexane = 3.58 x 100 / 4.001375 = 89.47 = 89.5%
Answer - C) 89.5%
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