The following reaction will not occur. 2Ag + FeCL_2 rightarrow Fe + 2AgCl A 3s o

Question

The following reaction will not occur. 2Ag + FeCL_2 rightarrow Fe + 2AgCl A 3s orbital is the same shape and size as a 2s orbital. The strongest intermolecular force in C_5H_12 is London Dispersion Forces. An endothermic reaction causes the surroundings to absorb heat. As intermolecular forces increase, vapor pressure decreases. If the volume of a gas is doubled at constant temperature, pressure will double. The principal quantum number of a 6s orbital is 1=0. A p subshell is given by quantum number l=l.

Explanation / Answer

31. )

Given reaction is single displacement reaction. In this Ag should displace Cl from FeCl2 in order to get product. Since the metal Ag is below to Fe in electrochemical series and it is less likely to oxidize than Fe so it will not be able to replace Cl from FeCl2. And the given statement is false.

32.)

Since size of the orbital depends on the principle quantum number. 3s orbital is having large size than 2s so the statement is false.

33)

Given molecule C5H12 is non polar and there exists only London forces and not any dipole or hydrogen bonding. So the strong forces in this molecule only London and given statement is true.

34)

The reaction which absorbs the heat is called as endothermic reaction. When it absorb the heat, heat of surrounding is lowered and so the given statement is false.

35 )

Vapor pressure is the pressure at equilibrium between vapor and liquid phase. It depends on the strength of intermolecular forces. Strong the intermolecular force, more energy is required to vaporize the molecule from liquid to vapor. So there is inverse relation between vapor pressure and intermolecular force and so given statement is false.

36 )

We know boyl’s law. According to this law the pressure is inversely proportional to the volume of the gas.

So when volume of gas doubled pressure should decrease to half.

And given statement is false.

37)

The principle quantum number is shown by n and so statement is false.

38)

There are orbital representation.

When l = 0 then orbital is s

When l = 1 then orbital is p

When l = 2 then orbital is d and so on..

So given statement is correct.

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