A 0.0100 mole sample of butane was burned in a bomb calorimeter. The heat from t
ID: 1056840 • Letter: A
Question
A 0.0100 mole sample of butane was burned in a bomb calorimeter. The heat from the reaction raised the temperature of 1.00 kg of water by 6.90 degree C. How much heat was released in this reaction per mole of butane combusted? The specific heat of water is 4.184 J/(g degree C). The combustion of 0.1584 grams of benzoic acid increases the temperature of a calorimeter by 2.54 degree C. Calculate the heat capacity of this calorimeter The energy released by the combustion of benzoic acid is 26.42 kJ/gram.Explanation / Answer
3)
heat released by 0.0100 mol = mw*Cw*delta T
= 1000 g * 4.184 J/goC * 6.90 oC
= 28869.6 J
heat released per mol = 28869.6 J / 0.0100 mol
= 2886960 J
= 2887 KJ
Answer: 2887 KJ/mol
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