optical Activity and Enantiomeric Analysis chapter 17 the 251 the concentration
ID: 1057313 • Letter: O
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optical Activity and Enantiomeric Analysis chapter 17 the 251 the concentration of solution match the concentration used for published your useful value of the specific rotation? ow accurate is the you to setting? all of these factors seem be in order, it is evaluate your to expected. in the reading that Questions A sample of 2-butanol has a specific rotation Determine the ee and the molecular composition of this sample. The specific rotation of pure 2-butanol is 13.0°. 2. A sample of 2-butanol (see question 1) has a specific rotation of -9.75. Determine the ee and the molecular composition of this sample. CHO, brucine and brucine (R CHO) are examples 4. Only one of the two nitrogens in strych of alkaloid bases that can be nine and brucine acts as the basic site used for acid-base reaction for a optical resolutions and enantiospecific for the necessary nitrogen, and why? lution. Which organic synthesis. These molecules are study gives a rich sources of chirality (5. n optical rotation +140° as the result. Suggest a dilution la]D 104° and -85° in absolute etha Assume that nitrogen inversion is experiment to test whether the result is nol). +140 not slow and identify the eight stereocenters indeed in each of these two nitrogen heterocyclic compounds.Explanation / Answer
1)
Given- specific rotation of 2-butanol = 3.250
If the + enantiomer is +13.00, then the - enantiomer is -13.00.
Let x = + enantiomer
1-x = - enantiomer.
Then x (13) + (1-x)(-13) = 3.25
13 x + (- 13 +13 x) = 3.25
26 x = 3.25 + 13 = 16.25
x = 16.25/26 = 0.625
1-x = 0.375
%ee = (R-S/R+S)*100
= [(0.625-0.375)/(0.625+0.375)]*100
= (0.25/1.0)*100 = 25%
2) Given- specific rotation of 2-butanol = - 9.750
If the + enantiomer is +13.00, then the - enantiomer is -13.00.
Let x = + enantiomer
1-x = - enantiomer.
Then x (13) + (1-x)(-13) = - 9.75
13 x + (- 13 +13 x) = - 9.75
26 x = - 9.75 + 13 = 3.25
x = 3.25/ 26 = 0.125
1-x = 0.875
%ee = (R-S/R+S)*100
= [(0.125-0.875)/(0.125+0.875)]*100
= (-0.750/1.0)*100 = - 75%
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