(a) A piston at 2.6 atm contains a gas that occupies a volume of 3.5 L. What pre
ID: 1057345 • Letter: #
Question
(a) A piston at 2.6 atm contains a gas that occupies a volume of 3.5 L. What pressure would have to be placed on the piston to force the volume to adjust to 1.35 L?
atm
(b) A piston at -10.0°C contains a gas that occupies a volume of 2.5 L. To what temperature would the gas have to be heated to increase the volume to 5.7 L at constant pressure?
°C
(c) A piston at 7295 torr contains a gas that occupies a volume of 4.7 L. What pressure would have to be placed on the piston to force the volume to adjust to 0.47 L?
atm
Explanation / Answer
a)
apply ideal gas law ratios
P1V1 = P2V2
2.6*3.5 = 1.35*P2
P2 = 2.6*3.5/1.35
P2 = 6.7407 atm
b)
apply ratios
V1/T1 = V2/T2
2.5/(-10+273) = 5.7/T2
T2 = 5.7/2.5*(263) = 599.64 K --> 600-273 = 326.64 C°
b)
P1V1 = P2V2
7295 * 4.7 = P2*0.47
P2 = 10*7295 = 72950 torr
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