Solutions of sodium hypochlorite, NaCIO (MW = 74.5), are sold, as bleach (such a

Question

Solutions of sodium hypochlorite, NaCIO (MW = 74.5), are sold, as bleach (such as Clorox). It is prepared by the reaction of chlorine with sodium hydroxide. 2 NaOH (aq) + Cl_2 (g) rightarrow NaC (aq) + NaClO (aq) + H_2O (l) If chlorine gas. Cl_2 (MW = 71.0). is bubbled into a solution 12.0 L of 5.25 M NaOH (MW = 40.0), how many grams of Cl_2 (MW = 71.0) will eventually react? If Bryce has a 65.0 L tank of chlorine at 25 degree C and a pressure of 13.61 atm and the %yield of this reaction is 86.0%, will he have enough Cl_2 to react with all the NaOH? R = 0.0821 L-atm/mol-K A person's daily caloric requirement can be obtained by ingesting about 726 g of glucose, C_6H_120_6 (MW = 180). Assume that glucose reacts completely with oxygen to give carbon dioxide and water. Calculate the volume of air needed at 20 degree C and 755 torr must be breathed to react with this much glucose, if air is 24.0% oxygen by volume. R = 62.4 liter-torr/mole-deg C_6H_12O_6(s) + 6 O_2(g) rightarrow 6 CO_2(B) + 6 H_2O(l) From a procedure for a vapor density experiment, Corey collected the following data: Barometric Pressure = 1.00 atmosphere; Boiling point of H_2O = 100.0 degree C mass of flask + septum: 97.5264 g mass of flask + septum + unknown: 97.9524 g mass of flask + septum + water: 232.03 g density of water = 1.00 g/ml; R = 0.0821 liter-atm/mole K; 1 liter = 1000 ml From this data, calculate the molecular weight of the unknown. If the percent composition is 24.7% C (At. Wt. = 12.0), 73.2% Cl (At Wt. = 35.5), and 2.1% H (At Wt = 1.0), determine the molecular formula. Draw all possible isomers. Do any of the isomers have a dipole and are polar molecules? NH_3 and the other containing HCl, at 25 degree C are connected by a a tube that is 1.00 times 10^2 cm long, which has a volume of 325 cm^3, where along this tube will the two gases meet and react? Each flask contains 25.5 g of reactant and the gases react until one is completely consumed. How much NH_4Cl will be made Which gas will be in excess and what will be the final pressure of the system after the reaction is complete? Assume the volume of the NH_4Cl is negligible. R = 0.0821 L-atm/mol-K

Explanation / Answer

NaClO

V = 12 L of M = 5.25 M of NaOH

mol of NaOH = MV = 12*5.25 = 63 mol of NaOH

then, since ration is 2:1

63/2 = 31.5 mol of Cl2 are required

mass = mol*MW = 31.5*70.9 = 2233.35 g of Cl2 react

V = 65 L of tank of CL2 gas...

find ytield

mol in tank = PV/(RT) = (13.61*65)/(0.082*298) = 36.20273 mol of chlorine

there is neough, since we only need 31.5

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