RD 375, 11:30 3. A Tengent for an atnospheric pressure industrial reactionnnust

Question

RD 375, 11:30 3. A Tengent for an atnospheric pressure industrial reactionnnust be vaporized at elevated temperature when being used. The reagent is storcd as a liquid in an insulated tank of capacity 9.2 Tr wilh an intemal healinut elemieni ilial can deliver 57 kW uxi ruyweT al itN naximun setting. When Lot in use, the reagent is kept at room temperature (25 C). When tbe reagent is used, the reagent must first be beated up to its vaporization temperature. When that temperature is hed, vapor is generated for the reaction. a) On a particular day. the tank is initially 60 fa Given the data below. what fiom the tank? What is Power once the vessel s brated? DATA carpa y a Heat capacity of vapor reagent: C JmolaC Heat xinviilien AH 34.9 Boiling point of reagent Th 133 C Molecular weight of reagent MW 110 d density of Tengem

Explanation / Answer

solution:

1)here given tank vome=V=9.2 m3

2)on that tank volume=V1=.6*V=5.52 m3

3)mass of reactant=density*V1=840*5.52=4636.8 kg

molecular weight=m=110 gm

4)here number of mole of reagent is

n=m/M=4636.8*10^3/110=42152.72 mole

5)for shorter time if all mole are contact with heatre to maximumcapcity Pmax=57000 j/s

hence power is given by for just vapor generation if all mole are in contact with heater

P=n'Cp(Tb-Ts)+n'Hv

hence time is n'=n/t

hence minimum time is give nas

t=nCp(Tb-Ts)+nHv/P=42152.7*176*(133-25)+42152.7*34900/57000

t=39866.10 sec

and if single mole is in contact with heater the time would

t=1*176*(133-25)+1*34900/57000=0.945754 sec

3)for power generation to be m'=300 kg/hr,power requirement for all moles is

P=n'Cp(Tb-Ts)+n'Hv

here n'=m'/M=300/110=2727.27 mol/hr

P=2727.27*176(133-25)+2727.27*34900=147021.818 kj/hr=40.8393 kj/s=40.8393 kw

Related Questions

Navigate

• Browse (All)
• Browse R
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.