50/50 blend of engine coolant and water (by volume) is usually used in an automo

Question

50/50 blend of engine coolant and water (by volume) is usually used in an automobile's engine cooling system. If your car's cooling system holds 6.30 gallons, what is the boiling point of the solution? Make the following assumptions in your calculation: at normal filling conditions, the densities of engine coolant and water are 1.11 g/mL and 0.998 g/mL respectively. Assume that the engine coolant is pure ethylene glycol (HOCH2CH2OH), which is non-ionizing and non-volatile, and that the pressure remains constant at 1.00 atm.

Explanation / Answer

First, we need to convert from 50/50 volume to molal (moles solute/kg solvent)

For 1 liter;

500ml x 1.11g/ml = 555g ethylene glycol
500ml x 0.998g/ml = 499g water


So: find moles ethylene glycol in 555g

555g/[(2 x 12.01) + (2 x 23.84) + (6 x 1.01)]g/mole = 555g/62.08g/mole = 7.13 moles
So,we founs that there are 7.13 moles in 499g water but, we need the moles in 1000g of water:

7.13mole x (1000g/499g) = 14.29 moles/kg water, so it is 14.29 molal

The boiling point should be 100 C+ (14.29 molal x 0.512 C/molal) = 107.31C

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