Glucose-1-phosphate + H_2 O rightarrow glucose + P_i delta G degree \' = -20.9 k

Question

Glucose-1-phosphate + H_2 O rightarrow glucose + P_i delta G degree ' = -20.9 kJ/mol. ATP + H_2 O glucose + P_i delta G degree ' = -30.5 kJ/mol Constants: R = 8.3145 J/mol K Eauations: delta G = delta G degree ' + RTlnO delta G degree ' = RTInK Assume that reactants and products are present in equimolar amounts. Draw an arrow in the direction the reaction will progress (ie leftarrow or rightarrow). Glucose + ATP rightarrow glucose-1-phosphate + ADP Determine the delta G degree ' (in kJ/mol) for the reaction in part a.

Explanation / Answer

1. the given reaction,

Glucose + ATP ---> Glucose-1-phosphate + ADP

will go in the forward direction. As dGo' is -ve in the forward direction.

The valid arrow woud be "--->" sign

2. For the reaction,

dGo' = 20.9 - 30.5

         = -9.6 kJ/mol

Related Questions

Navigate

• Browse (All)
• Browse G
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.