How many liters of a 12% (m/v) KOH solution would you need to obtain 86.0 g of K

Question

How many liters of a 12% (m/v) KOH solution would you need to obtain 86.0 g of KOH? How many liters of a 5.0% (m/v) glucose solution would you need to obtain 75 g of glucose? What is the molarity of a solution containing 8.0 g of NaOH in 400. mL of NaOH solution? What is the molarity of a solution containing 15.6 g of KCl in 274 mL of KC1 solution? How many milliliters of a 1.75 M LiCl solution contain 15.21 g of LiCl? How many milliliters of a 1.50 M NaBr solution contain75.0 g of NaBr? How many liters of a 2.50 M KNO_3 solution can be prepared from 60.0 g of KNO_3? How many liters of a 4.00 M NaCl solution will provide 25.0 g of NaCl?

Explanation / Answer

12.111 : 12gm of KOH is there in 100 ml of solution ( 12% m/V means)

80 gm are present in (80/12)*100ml =667ml = 667/1000=0.667L

12.112 similarly for glucose, (75/5)*100ml = 1500ml =1.5 L

12.113 molarity = moles of NaOH/ in 1 liter of solution, moles =mass/Molar mass = 8/40= 0.2

Molarity = 0.2/(400/1000)L= 0.2/0.4 =0.5M

12.114 molar mass of KCl= 74.5 , molairty = (15.6/74.5)/(274/1000) =0.764M

12.115   Molar mass of LICl = 42 g/mole, 1.75 M LICl means

1.75 moles = 1.75*42 gm are there in 1 L of the solution

73.5 gm are there in 1 L

15.2 gm will be there 15.2/73.5 L =0.21 L

12.116 Molar mass of NaBr=103, 1.5 Molar means 1.5 moles= 1.5*103 gm= 154.5 gm are there in 1 L solution.

75 gm are there in 75/154.5 L=0.485L

12.117 Molar mass of KNO3= 101, 2.5M means 2.5*101 gm of KNO3 in 1 L

60 gm are there in (60/2.5*101) L =.24 L

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