How many grams of potassium hydrogen phthalate are needed to prepare 250 mL of a

Question

How many grams of potassium hydrogen phthalate are needed to prepare 250 mL of a 0.1000 mol/L solution of potassium hydrogen phthalate. (MW= 204.23) (Round off answer to nearest 0.01 g.) Show calculations for dilution of the concentrated NaOH solution to obtain 250 mL of approximately 0.20 mol/L NaOH. Explain how this reagent should be prepared, i.e. the order of the steps. (Round off answer to nearest 0.01 mL.) Prepare a solution of 0.200 mol/L HCI to be used as a reagent. Show calculations for

Explanation / Answer

2) molarity of concnetrated sNaOH solution = 17mol/L = 17M

Volume of concentrated NaOH solution needed = ?

reuqired molarity = 0.20mol/L = 0.2M

volume of 0.20M solution required = 250mL

When diluting a solution we add only solvent thus number of mmoles of solute remain same before and after dilution.

thus MxV before dilution = M x V after dilution

17M x V (mL ) = 0.20 x 250mL

thus V = 2.9411mL

= 2.94 mL

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