a student was asked to determine the percentage of each component in a mixture o

Question

a student was asked to determine the percentage of each component in a mixture of PbCl2 and CaCO3 Mass of mixture = 4.85 g Mass of recovered CaCO3 = 3.21 g Mass of recovered PbCl2 = 1.03 g a student was asked to determine the percentage of each component in a mixture of PbCl2 and CaCO3 Mass of mixture = 4.85 g Mass of recovered CaCO3 = 3.21 g Mass of recovered PbCl2 = 1.03 g a student was asked to determine the percentage of each component in a mixture of PbCl2 and CaCO3 Mass of mixture = 4.85 g Mass of recovered CaCO3 = 3.21 g Mass of recovered PbCl2 = 1.03 g

Explanation / Answer

percentage of PbCl2 = mass of PbCl2*100/total mass

= 1.03*100/4.85

= 21.2 %

percentage of CaCO3= mass of CaCO3*100/total mass

= 3.21*100/4.85

= 66.2 %

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