Calculate the equilibrium constant for the reaction below at 25 degree C. PCl_2(

Question

Calculate the equilibrium constant for the reaction below at 25 degree C. PCl_2(g) doubleheadarrow PCl_2(g) + Cl_2(g) A) 0.981 B) 1.82 times 10^26 C) 1.47 times 10^-2 D) 4.50 times 10^3 What is the value of Delta G if the pressure in problem 13 were P_Cl_2 = 0.40 atm, P_PCIS = 0.27 atm and P_PCIS = 0.0029 atm A) 48 kJ B) 1.2 kJ C) 39 kJ D) 2.3 times 10^2 kJ Calculate the entropy change for the surroundings for the reaction at 298 degrees kelvin A) 3.14 J/k B) 6.86 times 10^3 J/k C) 5.30 times 10^2 J/k D) 456 J/k Which distribution of six particles into three interconnected boxes has the highest Delta S? A) a B) b C) c D) neither

Explanation / Answer

G rxn = G(PCl3) + G(Cl2) - G(PCl5)
= -286 + 0 - (-325)
= 39 KJ/mol
= 39000 J/mol

T = 25 oC = (25 + 273) K = 298 K

Now use:
G rxn = -R*T*ln K
39000 = -8.314*298*ln K
K = 1.47*10^-7

Answer: C

i am allowed to answer only 1 question at a time. Please ask other as different question

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.