The lab results correspond with the questions on the other packet as well. I\'m

Question

The lab results correspond with the questions on the other packet as well. I'm very lost on how to solve for any of this because we have not applied what we learned in a lab. procedure: activity 2 activity 2: determining the concentration of commercial hydrogen peroxide (H2O2) (guided inquiry) In this activity you will determine the concentration commercial concentration a solutions In order to do this, you must develop procedure determine the of solution using a iron This procedure should be very similar to the one you of performed in Activity 1.Once the KMno, solution is standardized, it can be used to determine the of exact concentration of the commercial Hao,create a data table for this procedure and record all your observations and data. 1. Before starting your experiment, show your experiment design to your instructor, for review. 2. Create a data table for your experiment. 3. Record the procedure that you used and all data you obtained. Hints: Materials you will use for the standardization of KMno. include: About 10 mL of 0.02 M KMno. 5-15 ml of acidified 0.100 MFe" solution To acidify the solution of Fe add 3 mL of 3MHaso Use the procedure for the standardization of KMno, as a guide in designing your procedure to determine the exact concentration of the H O2. In determining the concentration of the Hao use 1.00 mLof H o,as the analyte, and add 3 mL of 3MHzsole to the as H' is required for the reaction. Arthe end of this activity, clean up all materials and dispose of them according to your teachers instructions. Be sure to wash your hands thoroughly before leaving the laboratory 2013 ward Science Al rights reserved 70303-040 rev 6/15 Page S11

Explanation / Answer

Reaction with H2O2

moles of KMnO4 = 0.02 M x 10 ml = 0.2 mmol

molarity of KMnO4 = 0.02 M

moles of H2O2 = 0.2 mmol/2 = 0.1 mmol

mass of H2O2 = 0.1 x 34 = 3.4 mg

% H2O2 = 0.0034 x 100/1 = 0.34%

Reaction with Fe2+

moles of Fe2+ = 0.1 M x 10 ml = 1 mmol

moles of KMnO4 needed to reach equivalence point = 1/5 = 0.02 mmol

Balanced equation,

5Fe2+ + MnO4- + 8H+ --> 5Fe3+ + Mn2+ + 4H2O

molarity of KMnO4 = 0.02 mmol/39.3 ml = 0.51 mM (Trial 1)

molarity of KMnO4 = 0.02 mmol/31.3 ml = 0.639 mM (Trial 2)

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