University of Oklahoma X K- pling com Vibisc 2739347 gleaming Pt Dynamic Periodi

Question

University of Oklahoma X K- pling com Vibisc 2739347 gleaming Pt Dynamic Periodic k Canwas Print Calculator Periodic Table Question 8 of 30 Map Aa Sapling Learning macmilan learning The combustion of octane, C8H18, proceeds according to the reaction 2C If 4.50 x 102 mol of octane combusts, what volume of carbon dioxide is produced at 39.0 oC and 0.995 atm? Number Previous Check Answer Ney Si Frit Give on n View So Ask me a Available Due Date Points Po Grade Ca Descriptio Policies: You can c You can v up on any You have There is O eTextbo o Help O Web He O Technic :43 PM 12/1/2016

Explanation / Answer

according to given reaction,
2 mol of octane produces 16 moles of CO2

so,
moles of CO2 produced = 8*moles of Octane
= 8*4.50*10^2 mol
= 3600 mol

Now use:
P*V = n*R*T
0.995*V = 3600*0.0821*(39+273)
V = 9.27*10^4 L

Answer: 9.27*10^4 L

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