specific heat liquid = 0.1510 J/g°C A 23.60 g sample of liquid bismuth at 637.0

Question

specific heat liquid = 0.1510 J/g°C

A 23.60 g sample of liquid bismuth at 637.0 °C is poured into a mold and allowed to cool to 25.0 °C. How many kJ of energy are released in this process. Report the answer as a positive number.

_________ kJ

boiling point = 1.627×103 °C Hvap(1.627×103 °C) = 822.9 J/g melting point = 271.0 °C Hfus(271.0 °C) = 52.60 J/g specific heat solid = 0.1260 J/g°C

specific heat liquid = 0.1510 J/g°C

A 23.60 g sample of liquid bismuth at 637.0 °C is poured into a mold and allowed to cool to 25.0 °C. How many kJ of energy are released in this process. Report the answer as a positive number.

_________ kJ

Explanation / Answer

Q = Q (to take liquid from 637 oC to 271 oC) + Q (to freeze) + Q (to take solid from 271 oC to 25 oC)
= m*Cl*delta Tl + m*Lfus + m*Cs*delta Ts
= 23.60*0.1510*(637-271) + 23.60*52.60 + 23.60*0.1260*(271-25)
= 1304.3 + 1241.4 + 731.5
= 3277.2 J
= 3.28 KJ

Answer: 3.28 KJ

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