When solutions of silver nitrate and magnesium chloride are mixed, silver chlori

Question

When solutions of silver nitrate and magnesium chloride are mixed, silver chloride precipitates out of solution according to the equation 2AgNO3(aq)+MgCl2(aq)2AgCl(s)+Mg(NO3)2(aq)

Part A

What mass of silver chloride can be produced from 1.98 L of a 0.259 M solution of silver nitrate? Express your answer with the appropriate units.

Part B

The reaction described in Part A required 3.32 L of magnesium chloride. What is the concentration of this magnesium chloride solution?

Express your answer with the appropriate units.

Explanation / Answer

A)
from given reaction,
number of moles of AgCl = number of moles of AgNO3
=M(AgNO3)*V(AgNO3)
=0.259 M * 1.98 L
=0.513 mol

molar mass of AgCl = 143.32 g/mol

mass of AgCl = number of mol * molar mass
= 0.513 mol * 143.32 g/mol
= 73.5 g

Answer: 73.5 g

B)
form given reaction,
number of moles of MgCl2 = number of AgNO3/2
= 0.513/2
=0.2565 mol

Now use:
number of moles of MgCl2 = M(MgCl2)*V(MgCl2)
0.2565 = M * 3.32
M = 0.077 M

Answer: 0.077 M

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