Which of the following statements is false regarding the two-step energy diagram
ID: 1065501 • Letter: W
Question
Which of the following statements is false regarding the two-step energy diagram depicted below? A) Points b and d depict transition states. B) The reaction is endothermic. C) The conversion from points c to e is slower than the conversion from points a to c. D) An intermediate is formed in the first step of the reaction. E) All of the above statements are true A carbocation is all of the following except A) an electrophile B) a reactive intermediate C) Lewis acid D) an electron-rich species E) a species formed by heterolytic bond cleavage Draw the major product (Compound B) of the reaction shown below.Explanation / Answer
Which of the following is false regarding the two step energy diagram depicted below
Option c -answer
c. The conversion from points c to e is slower than conversion from point a to c
The reaction from a e is exothermic,
but c is an intermediate along the way (not a transition state).
Where b, and d are Transition states occur as energy maxima in the diagram (the peaks, not the valleys).
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A carbocation is all of the following except
a) an electrophile
b) a reactive intermediate
c) Lewis acid--answer
d) Electron rich species
d) a pieces formed by heterolytic bond cleavage
lewis acid :compound or ionic species which can acknowledge an electron combine from a giver compound.
Heterolytic Fission. For a situation the C particle conveys a positive charge it is known as a carbocation and for the situation it conveys both the electrons of the broken bond and is contrarily charged, it is instinctively called a Carbanion.
A carbocation is a particle with an emphatically charged carbon iota. Among the easiest illustrations are methenium CH+ 3, 2H+. Some carbocations may have at least two positive charges, on a similar carbon particle or on various molecules, for example, the ethylene dication C2H2
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