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9. 500ml of 0.3M HCLO4 is combined with 500ml of 0.2M Ca(OH)2. Calculate the mol

ID: 1066018 • Letter: 9

Question

9. 500ml of 0.3M HCLO4 is combined with 500ml of 0.2M Ca(OH)2. Calculate the molarity of H+, CLO4-, Ca+2 and OH- ions after the reaction.

10. Gasoline is used to fuel a 4000 pound car accelerating from 0-55 miles per hour. How many g of C8H18 are needed? Assume perfect efficiency. (hints: 1 kg=2.20 pound, 1 mile=1.61 km, j=kg m^2/s^2; E=1/2 mv^2)

C8H18(l) + 25/2 O2(g)8 CO2(g)+ 9H2O(g) Hrxn=-5074.1kj

11. Chlorine gas has a density d=7.64g/L at temperature T=30°C. What is the pressure in atm?

12. 10 atm of Ne is heatd from 10°C to 120°C. What is the pressure?

13. When of gypsum (calcium sulfate dihydrate also known as sheetrock) is heated to 350°F, water is released as it is converted to anhydrite (calcium sulfate). Sheetrock resists burnin in this way. The water is given off as steam (gaseous water vapor). How many L of steam is released from 23,000g sheet of gypsum wall board at 1 atm and 350°F?

CaSO4 2H2)(s)CaSO4(s) + H2)(g)

14. A 5.0g cooking oil is combusted releasing energy to heat 1000g of water from 21.3°C to 66.3°C. How many nutrition calories (cal) are releasaed from the bread? (1 Cal =1000cal=4180 J)

Explanation / Answer

9. 500ml of 0.3M HCLO4 is combined with 500ml of 0.2M Ca(OH)2. Calculate the molarity of H+, CLO4-, Ca+2 and OH- ions after the reaction.

V = 500 mL = 0.5 L; M = 0.3

mol of HClO4 = MV = 0.3*0.5 = 0.15 mol of HClO4

for base

V = 500 mL = 0.5 L; M = 0.3 --> MV = 0.10 mol of Ca(OH)2

limiting reactant is acid, since 2:1 ratio

so

0.15 mol of HCl react with 0.075 mol of Ca(OH)2 to form

2HClO4 + Ca(OH)2 = Ca(ClO4)2 + 2H2O

Vfinal = V1+V2 = 500+500 = 1000 mL = 1 L

[H+] = 0 since all racts

[ClO4-] = 0.15 / 1 = 0.15 M

[Ca+2] = 0.10 / 1 = 0.10 M

mol of OH left = 2*(0.10 ) - 0.15 = 0.05 mol

[OH-] = 0.05 /1 = 0.05 M

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