a weather balloon is inflated to a volume of 28.9 L at a pressure of 753 mmHg an
ID: 1067080 • Letter: A
Question
a weather balloon is inflated to a volume of 28.9 L at a pressure of 753 mmHg and a temperature of 25.0•C. The balloon rises in the atmosphere to an altitude where the pressure is 400. MmHg and the temperature is -13.0•C.Assuming the balloon can freely expand, calculate the volume of the balloon at this altitude. a weather balloon is inflated to a volume of 28.9 L at a pressure of 753 mmHg and a temperature of 25.0•C. The balloon rises in the atmosphere to an altitude where the pressure is 400. MmHg and the temperature is -13.0•C.
Assuming the balloon can freely expand, calculate the volume of the balloon at this altitude. a weather balloon is inflated to a volume of 28.9 L at a pressure of 753 mmHg and a temperature of 25.0•C. The balloon rises in the atmosphere to an altitude where the pressure is 400. MmHg and the temperature is -13.0•C.
Assuming the balloon can freely expand, calculate the volume of the balloon at this altitude.
Explanation / Answer
P1V1/T1 = P2V2/T2
P1 = 753 mmHg = 0.991 atm , V1 = 28.9 L , T1 = 250C = 298 K
P2 = 400 mmHg = 0.526 atm , V2 = ? , T2 = -130C = 260 K
V2 = (P1V1T2 / T1P2)
V2 = (0.991 x 28.9 x 260 /298 x 0.526 )
V2 = 7446.374 / 156.748
V2 = 47.5 L
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