a two stage rocket launch leaves its launch pad moving vertically with an averag

Question

a two stage rocket launch leaves its launch pad moving vertically with an average acceleration of 4 m/s^2. at 10 seconds after the launch, the first stage of the rocket (now without fuel) is released. the second stage now has an acceleration of 6 m/s^2.
how high is the rocket when the first stage seperates, how fast is the rocket moving upon first stage seperation, what will the maximum height attained by the first stage after seperation and what will be the distance between the first and second stages 2 seconds after seperation?

Explanation / Answer

v=4*10 =40 m/s s =at*t/2 =4*100/2 =200 m max height = u*u/2g =1600/2*9.8 = 7.84 kms

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